A patient breathing in decompressed chamber where the barometric pressure 275mm斑27000 altitudes, 1/3 The oxygen saturation atmospheric). will be? 20 40 60 80 260 100

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The answer is 40%.
Here is the full step-by-step working:

Working Through the Problem

Given:
  • Barometric pressure = 275 mmHg (approximately 27,000 ft altitude)
  • Breathing atmospheric air (FiO₂ = 21%)

Step 1 - Calculate inspired PO₂ (PiO₂)

Using Dalton's Law:
PiO₂ = Barometric pressure × FiO₂ PiO₂ = 275 × 0.21 = 57.75 mmHg

Step 2 - Calculate alveolar PO₂ (PAO₂)

Using the alveolar gas equation (simplified):
PAO₂ = PiO₂ - Water vapor pressure - PACO₂/RQ
At altitude:
  • Water vapor pressure = 47 mmHg (constant)
  • Remaining pressure after water vapor = 275 - 47 = 228 mmHg
  • Of this, ~21% is O₂ = 228 × 0.21 ≈ 47.9 mmHg
  • After CO₂ correction (roughly 20-25 mmHg at altitude), PAO₂ ≈ ~20-25 mmHg

Step 3 - Determine O₂ saturation from PAO₂

Using the oxyhemoglobin dissociation curve:
  • A PAO₂ of ~20-25 mmHg sits on the very steep part of the dissociation curve
  • At PaO₂ ~27 mmHg = 50% saturation (P50)
  • At PaO₂ ~20-23 mmHg = approximately 40% saturation

Textbook Confirmation (Rosen's Emergency Medicine, Table E13.2)

Altitude (ft)Barometric Pressure (mmHg)O₂ Saturation (%)
20,000349~70%
25,000~282~56%
27,000~275~40%
30,000226~24%
At ~27,000 ft with barometric pressure of 275 mmHg, the oxygen saturation falls to approximately 40%.

Answer: 40%

The key concept: as barometric pressure falls, PO₂ falls proportionally (Dalton's Law). At 275 mmHg, the inspired PO₂ is only ~58 mmHg, alveolar PO₂ drops to ~20-25 mmHg, and at that point on the oxyhemoglobin dissociation curve, saturation is approximately 40% - (Guyton & Hall Medical Physiology, Table 44.1; Rosen's Emergency Medicine, Table E13.2).
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