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Hey! How can I help you today?## Solution
Using Coulomb's Law, the electrostatic force between two charges equals the tension in the string (since the system is in equilibrium on a frictionless surface).
Given:
- q₁ = q₂ = 2 × 10⁻⁸ C
- r = 1 m
- k = 9 × 10⁹ N·m²/C²
Formula:
$$T = F = k \frac{q_1 q_2}{r^2}$$
Calculation:
$$T = 9 \times 10^9 \times \frac{(2 \times 10^{-8}) \times (2 \times 10^{-8})}{(1)^2}$$
$$T = 9 \times 10^9 \times \frac{4 \times 10^{-16}}{1}$$
$$T = 9 \times 4 \times 10^{9-16}$$
$$T = 36 \times 10^{-7}$$
$$\boxed{T = 3.6 \times 10^{-6} \text{ N}}$$
Answer: Option 1 - 3.6 × 10⁻⁶ N
The tension in the string equals the repulsive Coulomb force between the two charges, since both charges repel each other and the string is what keeps them at a fixed separation.
In simple language
Simple Explanation
What's happening?
Two charged balls are tied together with a string on a table. Since both have the same charge, they repel (push away) each other. The string stops them from flying apart — so the string is under tension.
The tension = the pushing force between the charges
The formula is:
Force = 9 × 10⁹ × (charge 1 × charge 2) / (distance)²
Just plug in the numbers:
- Both charges = 2 × 10⁻⁸ C
- Distance = 1 m
Step 1: Multiply the two charges
2 × 10⁻⁸ × 2 × 10⁻⁸ = 4 × 10⁻¹⁶
Step 2: Multiply by 9 × 10⁹
9 × 10⁹ × 4 × 10⁻¹⁶ = 36 × 10⁻⁷
Step 3: Write it properly
36 × 10⁻⁷ = 3.6 × 10⁻⁶ N
✅ Answer: Option 1 → 3.6 × 10⁻⁶ N
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