I now have all the information needed from the textbook sources to write excellent 2-mark reasoning answers. Let me compose them.
Here are the 2-mark reasoning answers based on DM Vasudevan's Textbook of Biochemistry for Medical Students and corroborating sources from Harper's and other standard references:
a) Vitamin E is called a chain-breaking antioxidant
Vitamin E (alpha-tocopherol) acts as a chain-breaking, free radical-trapping antioxidant primarily in cell membranes and plasma lipoproteins. When polyunsaturated fatty acids (PUFAs) undergo lipid peroxidation, they generate lipid peroxide radicals (ROO•) that propagate a damaging chain reaction. Vitamin E donates a hydrogen atom to ROO•, converting it into a stable lipid hydroperoxide (ROOH) and generating a relatively unreactive tocopheroxyl radical. This interrupts (breaks) the propagation chain of free radical reactions, preventing further membrane damage. The tocopheroxyl radical is then regenerated back to tocopherol by Vitamin C, completing the antioxidant cycle.
(Harper's Illustrated Biochemistry, 32nd Ed.)
b) Restriction endonucleases show different cleavage patterns
Restriction endonucleases recognize specific palindromic sequences (usually 4-8 base pairs) in double-stranded DNA and cleave them. Different enzymes exhibit different cleavage patterns because:
- Blunt-end cuts - both strands are cut at exactly opposite positions, producing flush (blunt) ends.
- Staggered (sticky-end) cuts - the two strands are cut at different positions within the palindrome, generating short single-stranded overhangs called cohesive or sticky ends (either 5' overhangs or 3' overhangs, depending on the enzyme).
The difference in cutting pattern arises from the specific geometry of the enzyme's active site relative to its recognition sequence. For example, EcoRI cuts to produce 5' overhangs, while KpnI produces 3' overhangs, and SmaI produces blunt ends - all because each enzyme positions its catalytic residues differently on the DNA backbone.
c) Compensatory mechanisms in Metabolic Acidosis
In metabolic acidosis, the primary defect is a fall in plasma HCO3-, which reduces the HCO3-/CO2 ratio below 20:1, causing pH to drop below 7.35. Two compensatory mechanisms act to restore pH:
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Respiratory compensation (immediate): The fall in pH stimulates peripheral and central chemoreceptors, causing hyperventilation (Kussmaul respiration). This blows off CO2, reducing pCO2 (hypocapnia), which decreases dissolved CO2 (cdCO2) and thereby corrects the HCO3-/cdCO2 ratio back toward 20:1, raising pH toward normal.
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Renal compensation (slower, hours to days): The kidneys respond by:
- Increased H+ excretion (increased Na+/H+ exchange in the tubules)
- Increased ammonia (NH3) production and excretion as NH4+
- Increased reabsorption of HCO3-, restoring plasma bicarbonate
Together, these mechanisms can fully compensate metabolic acidosis and return pH to 7.40, though the underlying bicarbonate deficit persists.
(Tietz Textbook of Laboratory Medicine, 7th Ed.)
d) Coumarin group of drugs act as anticoagulants
Coumarin drugs (e.g., warfarin) act as anticoagulants by antagonizing Vitamin K. Vitamin K is required as a coenzyme for the posttranslational carboxylation of glutamate (Glu) residues to gamma-carboxyglutamate (Gla) in coagulation factors II (prothrombin), VII, IX, and X, as well as anticoagulant proteins C and S. The Gla residues chelate Ca2+ ions, enabling these factors to bind to phospholipid membranes and participate in coagulation.
Coumarins inhibit vitamin K epoxide reductase, the enzyme that converts the inactive vitamin K quinone form back to its active hydroquinone form. Without active vitamin K, the Glu-to-Gla carboxylation cannot occur, resulting in the production of biologically inactive, incompletely carboxylated coagulation factors, and thus impaired clotting. Administration of exogenous vitamin K reverses this inhibition within 12-24 hours.
(Harper's Illustrated Biochemistry, 32nd Ed.)
e) Degeneracy of the genetic code and the wobbling phenomenon together reduce the effect of mutations
Degeneracy means that most amino acids are encoded by more than one codon (synonymous codons, totaling 64 codons for 20 amino acids + stop signals). Most synonymous codons differ only in the 3rd (wobble) position of the codon triplet.
The wobble hypothesis (Crick, 1966) states that the base-pairing between the 3rd nucleotide of the codon and the 1st nucleotide of the anticodon is flexible ("wobbles") - a single tRNA can recognize multiple codons differing at the 3rd position. For example, inosine (I) at the 5' end of an anticodon can pair with U, C, or A; thus codons GGU, GGC, and GGA can all be read by the anticodon 3'CCI5'.
Together, they reduce mutation effects as follows: A point mutation at the 3rd codon position (the most common "silent" or synonymous mutation) often changes one synonymous codon to another that codes for the same amino acid, because the wobble allows the same tRNA to read both. As a result, the mutation produces no change in the amino acid sequence of the protein - a silent (neutral) mutation. This greatly buffers the genome against the phenotypic consequences of single base substitutions.
(Harper's Illustrated Biochemistry, 32nd Ed.)