3 cm height 5.5 length Hey, Claude. This is the calculation. So I want the exact, uh, weight in grams, which these, uh, vessels can be have, like, which is the maximum weight this vessel have, not the vessel weight. Okay? The quantity if in this vessel I am taking the rise means what is the exact amount of rise? Can I take in this vessel? Okay. That's my question.
Asking for Preferences
This is a ladle (soup ladle) with a spherical/hemispherical bowl. The dimensions you gave are:
- Depth (height): 3 cm
- Diameter: 5.5 cm → Radius = 2.75 cm
Volume of the Ladle Bowl
The ladle bowl is a hemisphere-like shape (a spherical cap). Since the depth (3 cm) is slightly more than the radius (2.75 cm), it's approximately a full hemisphere.
Using the spherical cap formula:
V = π × h² × (3r - h) / 3
Where:
- h = depth = 3 cm
- r = sphere radius
First, find the sphere radius from the cap geometry:
r_sphere = (a² + h²) / (2h) = (2.75² + 3²) / (2×3) = (7.5625 + 9) / 6 = 16.5625 / 6 = 2.76 cm
Now calculate volume:
V = π × 3² × (3 × 2.76 - 3) / 3 V = π × 9 × (8.28 - 3) / 3 V = π × 9 × 5.28 / 3 V = π × 15.84 V ≈ 49.76 mL ≈ 50 mL
Maximum Weight of Water / Rice the Ladle Can Hold
Water (density = 1 g/mL):
~50 grams (maximum)
Rice (uncooked) - Your Main Question
Uncooked rice has a bulk density of about 0.85 g/mL (it doesn't pack perfectly due to gaps between grains).
Weight of rice = 50 mL × 0.85 g/mL = ~42–45 grams
In terms of quantity:
- 1 standard cup = 180–200 g of uncooked rice
- This ladle holds roughly ¼ of a standard cup
- Approximately 3 to 3.5 tablespoons of uncooked rice
Summary
| Contents | Max Weight |
|---|---|
| Water | ~50 g |
| Uncooked rice | ~42–45 g |
| Cooked rice | ~47–48 g (density ~0.95 g/mL) |
So in this ladle, you can fit approximately 42–45 grams of uncooked rice at maximum capacity.
This is a shared conversation. Sign in to Orris to start your own chat.