The WARBURG Effect refers to the following: a. Pure oxidative phosphorylation b. Neither c. Exhaustion of carbon molecules for building protein d. Both
Reading Document
Medical Text Search
Warburg effect aerobic glycolysis cancer metabolism
GradeResponse
The answer is b. Neither — but let me explain precisely why.
The Warburg Effect
The Warburg Effect (described by Otto Warburg) refers to the phenomenon where proliferating tumor cells preferentially use aerobic glycolysis — that is, they convert glucose to lactate even in the presence of oxygen, rather than using the more efficient oxidative phosphorylation.
According to Harrison's Principles of Internal Medicine (p. 2081):
"Proliferative tumor tissues, especially in the setting of hypoxia, use aerobic glycolysis to generate energy for cell survival and generation of building blocks for new cells."
This is explicitly contrasted with normal differentiated tissues, which rely on oxidative phosphorylation and generate ~36 ATP molecules per glucose molecule.
Why the answer is b. Neither:
| Option | Why it's wrong |
|---|---|
| a. Pure oxidative phosphorylation | This is what normal tissues do — the Warburg effect is the opposite |
| c. Exhaustion of carbon molecules for building protein | This mischaracterizes the effect; carbon intermediates from glycolysis are diverted for biosynthesis (nucleotides, lipids, amino acids), not exhausted |
| d. Both | Both a and c are incorrect, so "both" is also wrong |
The Warburg Effect specifically describes aerobic glycolysis — the use of glycolysis for energy and production of biosynthetic building blocks even when oxygen is available, a hallmark of cancer metabolism.
This is a shared conversation. Sign in to Orris to start your own chat.